(x^3/4)-6x=(x^2/2)

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Solution for (x^3/4)-6x=(x^2/2) equation: 


x in (-oo:+oo)

(x^3)/4-(6*x) = (x^2)/2 // - (x^2)/2

(x^3)/4-((x^2)/2)-(6*x) = 0

(x^3)/4-((x^2)/2)-6*x = 0

1/4*x^3-1/2*x^2-6*x = 0

x*(1/4*x^2-1/2*x-6) = 0

1/4*x^2-1/2*x-6 = 0

DELTA = (-1/2)^2-(-6*1/4*4)

DELTA = 25/4

DELTA > 0

x = ((25/4)^(1/2)+1/2)/(1/4*2) or x = (1/2-(25/4)^(1/2))/(1/4*2)

x = 6 or x = -4

x = 0

x = 0

x in { -4, 6, 0 }

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